import inout.Console;
 
/**
 *
 * @author Михайл Скиба <michael.skiba@rub.de>
 */
public class Crypto {
 
    public static void main(String args[]) {
        while (true) {
            int a, p, remainder=0, counter = 0;
            System.out.println("Please enter a");
            a = Console.readInt();
            System.out.println("Please enter p (must be prime)");
            p = Console.readInt();
 
            if (!isPrime(p)) {
                System.out.println(p + " is not a prime number!");
                System.exit(0);
            }
 
            do {
                counter++;
                // remainder = (int) (Math.pow(a, counter) %p);
                if(counter == 1){
                    remainder = a;
                }else{
                    remainder = (remainder * a) %p;
                }
/* Debug-Line: */System.out.printf("%d^%d = %d mod %d\n", a, counter, remainder, p);
            } while (remainder != 1);
            System.out.printf("ord(%d)= %d", a, counter);
            if (counter == (p - 1)) {
                System.out.printf(" (%d is a primitiv element)\n", a);
            }
 
            System.out.println("Continue y?");
            if(!Console.readString().equalsIgnoreCase("y")){
                System.exit(0);
            }
        }
    }
 
    // Shamelessly stolen from the interwebs ... 
    // http://stackoverflow.com/questions/2385909/what-would-be-the-fastest-method-to-test-for-primality-in-java
    public static boolean isPrime(int n) {
        return !new String(new char[n]).matches(".?|(..+?)\\1+");
    }
}